3y-y^2=y(1-y)+42

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Solution for 3y-y^2=y(1-y)+42 equation:


Simplifying
3y + -1y2 = y(1 + -1y) + 42
3y + -1y2 = (1 * y + -1y * y) + 42
3y + -1y2 = (1y + -1y2) + 42

Reorder the terms:
3y + -1y2 = 42 + 1y + -1y2

Add 'y2' to each side of the equation.
3y + -1y2 + y2 = 42 + 1y + -1y2 + y2

Combine like terms: -1y2 + y2 = 0
3y + 0 = 42 + 1y + -1y2 + y2
3y = 42 + 1y + -1y2 + y2

Combine like terms: -1y2 + y2 = 0
3y = 42 + 1y + 0
3y = 42 + 1y

Solving
3y = 42 + 1y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-1y' to each side of the equation.
3y + -1y = 42 + 1y + -1y

Combine like terms: 3y + -1y = 2y
2y = 42 + 1y + -1y

Combine like terms: 1y + -1y = 0
2y = 42 + 0
2y = 42

Divide each side by '2'.
y = 21

Simplifying
y = 21

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